Chapter 6 Oxidation and Reduction(RedoxReaction)Fourissues:1.Basicknowledge2.StandardReductionPotentials3.Introduction of Voltaic Cells4.Electrolysis and Electrolytic Cells
Chapter 6 Oxidation and Reduction (Redox Reaction) Four issues： 1. Basic knowledge 2. Standard Reduction Potentials 3. Introduction of Voltaic Cells 4. Electrolysis and Electrolytic Cells
1Basicknowledge1-1 Concepts1-2BalancingRedox Equations1-3Voltaiccells1-3-1 What kinds of redox reactionsbecanharnessed to produce electrical energy?1-3-2 Electrode Types and Cell Notation1-3-3CellPotentials
1 Basic knowledge 1-1 Concepts 1-2 Balancing Redox Equations 1-3 Voltaic cells 1-3-1 What kinds of redox reactions can be harnessed to produce electrical energy? 1-3-2 Electrode Types and Cell Notation 1-3-3 Cell Potentials
1-1ConceptsZn+Cu2+=Zn2++CuC,Hi20,+6 0,=6 CO, +6H,0(1)OxidationNumber假设分子中成键的电子都归电负性较大的原子，而得到的某元素的一个原子所带的形式电荷数（表观电荷数）
1-1 Concepts Zn + Cu2+ = Zn2+ + Cu C6H12O6 + 6 O2 = 6 CO2 + 6 H2O (1) Oxidation Number 假设分子中成键的电子都归电负性较大的原子，而得到 的某元素的一个原子所带的形式电荷数（表观电荷数）
Rules for assigning oxidation number:The oxidation number of an element in an elementarysubstanceisO.Generally, in compounds, the oxidation number of His+1 , the oxidation number of O is-2,the oxidation numberof halide F is -l,the oxidation number of Group 1 metals(IA)is +1,theoxidation number of Group2 elements(IlA)is +2.The sum of the oxidation numbers of all the atoms in aneutral species is O; in an ion, it is equal to the charge of thation
Rules for assigning oxidation number： u The oxidation number of an element in an elementary substance is 0. u Generally, in compounds, the oxidation number of H is +1 ，the oxidation number of O is -2, the oxidation number of halide F is -1, the oxidation number of Group 1 metals(IA) is +1, the oxidation number of Group 2 elements( IIA ) is +2. u The sum of the oxidation numbers of all the atoms in a neutral species is 0; in an ion, it is equal to the charge of that ion
Eg.S4O.2-, 0xid.no.S× 4 +2x6 =-2, 0xid.no.S=2.5CrO,0xid.no.Cr+ 2x5=0;oxid.no.Cr=-10Thus, the oxidation number of can be integers or fractions
Eg. S4O6 2- , oxid. no. S 4 + 26 = -2, oxid. no. S = 2.5 CrO5 oxid. no. Cr + 25 = 0 ; oxid. no. Cr = -10 Thus, the oxidation number of can be integers or fractions